Updated On: 04 March, 2024 07:20 AM IST | Acapulco (Mexico) | AP
The third-seeded De Minaur won his eighth ATP title to become the fourth player to repeat as champion in Mexico, the first since David Ferrer in 2010-12

Australia’s Alex De Minaur celebrates with the trophy in Acapulco on Saturday. Pic/AFP
Alex De Minaur beat Casper Rudd 6-4, 6-4 on Saturday to become the first player to win back-to-back titles in the Mexican Open since 2012.
The third-seeded De Minaur won his eighth ATP title to become the fourth player to repeat as champion in Mexico, the first since David Ferrer in 2010-12.